Cos^2x+2sinx=2

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Solution for Cos^2x+2sinx=2 equation: 


Simplifying
Cos2x + 2sinx = 2

Reorder the terms:
2insx + os2xC = 2

Solving
2insx + os2xC = 2

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1os2xC' to each side of the equation.
2insx + os2xC + -1os2xC = 2 + -1os2xC

Combine like terms: os2xC + -1os2xC = 0
2insx + 0 = 2 + -1os2xC
2insx = 2 + -1os2xC

Divide each side by '2nsx'.
i = n-1s-1x-1 + -0.5n-1osC

Simplifying
i = n-1s-1x-1 + -0.5n-1osC

Reorder the terms:
i = -0.5n-1osC + n-1s-1x-1

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